1. Tardigrade
  2. Question
  3. Chemistry
  4. At 298 K, the enthalpy of fusion of a solid (X) is 2.8 kJ mol -1 and the enthalpy of vaporisation of the liquid (X) is 98.2 kJ mol -1. The enthalpy of sublimation of the substance (X) in kJ mol -1 is (in nearest integer)

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Q. At $298\, K$, the enthalpy of fusion of a solid $(X)$ is $2.8\,kJ\,mol ^{-1}$ and the enthalpy of vaporisation of the liquid $(X)$ is $98.2 kJ\,mol ^{-1}$. The enthalpy of sublimation of the substance $(X)$ in $kJ\,mol ^{-1}$ is________ (in nearest integer)

JEE MainJEE Main 2021Thermodynamics

Solution:

$\Delta H_{\text {sub }}=\Delta H_{\text {fivs. }}+\Delta H_{\text {vap. }}$
$=2.8+98.2$
$=101\, kJ / mol$