At 25° C the specific conductivity of a normal solution of KCl is 0.002765 mho. The resistance of cell is 400 ohms. The cell constant is:

Question

At 25° C the specific conductivity of a normal solution of KCl is 0.002765 mho. The resistance of cell is 400 ohms. The cell constant is: (A) 0.815 (B) 1.016 (C) 1.106 (D) 2.016

Tardigrade Admin · Accepted Answer

We know that cell constant =(specific text conductivity/observed text conductance) Here, specific conductance = 0.002765 observed conductance =(1/R) =(1/400) ∴ cell constant =0.002765× 400 =1.106

Q. At $25^{\circ} C$ the specific conductivity of a normal solution of $K Cl$ is 0.002765 mho. The resistance of cell is 400 ohms. The cell constant is:

0.815

1.016

1.106

2.016

We know that cell constant $= \frac{s p ec i f i c co n d u c t i v i t y}{o b ser v e d co n d u c t an ce}$ Here, specific conductance = 0.002765 observed conductance $= \frac{1}{R}$ $= \frac{1}{400}$ $∴$ cell constant $= 0.002765 \times 400$ $= 1.106$

Q. At 25∘C the specific conductivity of a normal solution of KCl is 0.002765 mho. The resistance of cell is 400 ohms. The cell constant is: