1. Tardigrade
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  3. Chemistry
  4. At 25° C the specific conductivity of a normal solution of KCl is 0.002765 mho. The resistance of cell is 400 ohms. The cell constant is:

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Q. At $ 25{}^\circ C $ the specific conductivity of a normal solution of $ KCl $ is 0.002765 mho. The resistance of cell is 400 ohms. The cell constant is:

ManipalManipal 2000

Solution:

We know that cell constant $ =\frac{specific\text{ }conductivity}{observed\text{ }conductance} $ Here, specific conductance = 0.002765 observed conductance $ =\frac{1}{R} $ $ =\frac{1}{400} $ $ \therefore $ cell constant $ =0.002765\times 400 $ $ =1.106 $