Question

At $100^{\circ }C$ and $1atm$, if the density of the liquid water is $1.0gc{m}^{-3}$ and that of water vapour is $0.0006gc{m}^{-3}$, then the volume occupied by water molecules in $1L$ of steam at this temperature is

• A. 6 cc
• B. 60 cc
• C. 0.6 cc
• D. 0.06 cc
• E. 0.006 cc

Answer 1

Answer: (C)

For water vapours, $d=0.0006gc{c}^{-1}$

$0.0006-\frac{\text{ Mass }}{\text{ Volume }}=\frac{\text{ Mass }}{1000}$

$\text{ Mass }=1000\times 00006=0.6g$

Density of liquid water $=1gc{c}^{-1}$

Volume occupied by water

$=\frac{\text{ Mass }}{\text{ density }}=\frac{0.6}{1}=0.6cc$