Question

At $100^{\circ} C$ and $1 atm$, if the density of the liquid water is $1.0\, gcm ^{-3}$ and that of water vapour is $0.0006\,gcm ^{-3}$, then the volume occupied by water molecules in $1\, L$ of steam at this temperature is

• A. 6 cc
• B. 60 cc
• C. 0.6 cc
• D. 0.06 cc
• E. 0.006 cc

Answer 1

Answer: (C)

For water vapours, $d=0.0006 g cc ^{-1}$

$0.0006-\frac{\text { Mass }}{\text { Volume }} =\frac{\text { Mass }}{1000} $

$\text { Mass } =1000 \times 00006=0.6 g$

Density of liquid water $=1 g\, cc ^{-1}$

Volume occupied by water

$=\frac{\text { Mass }}{\text { density }}=\frac{0.6}{1}=0.6\, cc$