Assuming fully decomposed, the volume of CO2 released at STP on heating 9.85 g of BaCO3 (at. mass of Ba = 137 ) will be

Question

Assuming fully decomposed, the volume of CO2 released at STP on heating 9.85 g of BaCO3 (at. mass of Ba = 137 ) will be (A) 1.12 L (B) 0.84 L (C) 2.24 L (D) 4.96 L

Tardigrade Admin · Accepted Answer

On decomposition, BaCO 3 liberates CO 2 as underset197 gBaCO 3 longrightarrow BaO + underset22.4 L textat STPCO2 ∵ 197 g text of BaCO 3 gives =22.4 L text of CO 2 at STP ∴ 9.85 g text of BaCO 3 will give =(22.4 × 9.85/197)=1.12 L

Q. Assuming fully decomposed, the volume of $C O_{2}$ released at STP on heating $9.85 g$ of $B a C O_{3}$ (at. mass of $B a = 137$ ) will be

1.12 L

0.84 L

2.24 L

4.96 L

On decomposition, $B a C O_{3}$ liberates $C O_{2}$ as
$197 g B a C O_{3} ⟶ B a O + 22.4 L at STP C O_{2}$
$∵ 197 g of B a C O_{3}$ gives $= 22.4 L of C O_{2}$ at STP
$∴ 9.85 g of B a C O_{3}$ will give $= \frac{22.4 \times 9.85}{197} = 1.12 L$

Q. Assuming fully decomposed, the volume of CO2​ released at STP on heating 9.85g of BaCO3​ (at. mass of Ba=137 ) will be