Question

Assume carbon burns according to following equation :
$2C_{(s)}+O_{2(g)}\to 2CO(g)$
when $12g$ carbon is burnt in $48g$ of oxygen, the volume of carbon monoxide produced is___ $\times 10^{-1}L$ at STP [nearest integer]
[Given : Assume $CO$ as ideal gas, Mass of $C$ is $12gmo{l}^{-1}$, Mass of $O$ is $16gmo{l}^{-1}$ and molar volume of an ideal gas at STP is $22.7Lmo{l}^{-1}$ ]

Answer 1

Answer: 227

$\underset{\text{ 1 mol}}{2C(s)}+\underset{\text{1.5 mol}}{O_2(g)}\to 2CO(g)$
Limiting reagent is carbon. One mole carbon produces one mole $CO$. Hence, volume at STP is $227\times 10^{-1}$ litre