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  4. Assume carbon burns according to following equation: 2 C ( s )+ O 2( g ) arrow 2 CO ( g ) when 12 g carbon is burnt in 48 g of oxygen, the volume of carbon monoxide produced is × 10-1 L at STP [nearest integer] [Given: Assume CO as ideal gas, Mass of C is 12 g mol -1, Mass of O is 16 g mol -1 and molar volume of an ideal gas at STP is 22.7 L mol -1 ]

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Q. Assume carbon burns according to following equation :
$2 C _{( s )}+ O _{2( g )} \rightarrow 2 CO ( g )$
when $12\, g$ carbon is burnt in $48 \,g$ of oxygen, the volume of carbon monoxide produced is___ $\times 10^{-1} L$ at STP [nearest integer]
[Given : Assume $CO$ as ideal gas, Mass of $C$ is $12\, g \,mol ^{-1}$, Mass of $O$ is $16 \,g \,mol ^{-1}$ and molar volume of an ideal gas at STP is $22.7\, L\, mol ^{-1}$ ]

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Solution:

$\underset{\text{ 1 mol}}{2 C ( s )}+\underset{\text{1.5 mol}}{ O _2( g )} \rightarrow 2 CO ( g )$
Limiting reagent is carbon. One mole carbon produces one mole $CO$. Hence, volume at STP is $227 \times 10^{-1}$ litre