Assertion :The semiconductor used for fabrication of visible LEDs must at least have a band gap of 1.8 eV Reason :The spectral range of visible light is from 0.4 eV to 1.8 eV.

Question

Assertion :The semiconductor used for fabrication of visible LEDs must at least have a band gap of 1.8 eV Reason :The spectral range of visible light is from 0.4 eV to 1.8 eV. (A) If both assertion and reason are true and reason is the correct explanation of assertion. (B) If both assertion and reason are true but reason is not the correct explanation of assertion. (C) If assertion is true but reason is false. (D) If both assertion and reason are false.

Tardigrade Admin · Accepted Answer

The spectral range of visible light is from about 3 eV to 1.8 eV. Therefore the semiconductor used for fabrication of visible LEDs must at least have a band gap of 1.8 eV.

Q. Assertion :The semiconductor used for fabrication of visible LEDs must at least have a band gap of $1.8 e V$
Reason :The spectral range of visible light is from $0.4 e V$ to $1.8 e V$ .

If both assertion and reason are true and reason is the correct explanation of assertion.

If both assertion and reason are true but reason is not the correct explanation of assertion.

If assertion is true but reason is false.

If both assertion and reason are false.

The spectral range of visible light is from about $3 e V$ to $1.8 e V$ . Therefore the semiconductor used for fabrication of visible LEDs must at least have a band gap of $1.8 e V$ .

Q. Assertion :The semiconductor used for fabrication of visible LEDs must at least have a band gap of 1.8eV Reason :The spectral range of visible light is from 0.4eV to 1.8eV.