Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Assertion :The semiconductor used for fabrication of visible LEDs must at least have a band gap of $1.8 \,eV$
Reason :The spectral range of visible light is from $0.4\, eV$ to $1.8 \,eV$.

Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

The spectral range of visible light is from about $3 \,eV$ to $1.8 \,eV$. Therefore the semiconductor used for fabrication of visible LEDs must at least have a band gap of $1.8\, eV$.