Assertion: An emf vecE is induced in a closed loop where magnetic flux is varied. The induced vecE is not a conservative field. Reason: The line integral vecE×dl around the closed loop is nonzero.

Question

Assertion: An emf vecE is induced in a closed loop where magnetic flux is varied. The induced vecE is not a conservative field. Reason: The line integral vecE×dl around the closed loop is nonzero. (A) If both assertion and reason are true and reason is the correct explanation of the assertion (B) If both assertion and reason are true but reason is not the correct explanation of the assertion (C) If assertion is true, but reason is false (D) Both assertion and reason are false statements

Tardigrade Admin · Accepted Answer

A and R is true and R explains A. According to Faraday's law of electromagnetic induction. ∫ vec E ⋅ d vec l =( d φ/ dt ) So, ( E ) is non-conservative field as in conservative field line integral over a closed loop is zero.

Q. Assertion : An emf $E$ is induced in a closed loop where magnetic flux is varied. The induced $E$ is not a conservative field.
Reason : The line integral $E \times d l$ around the closed loop is nonzero.

If both assertion and reason are true and reason is the correct explanation of the assertion

If both assertion and reason are true but reason is not the correct explanation of the assertion

If assertion is true, but reason is false

Both assertion and reason are false statements

A and $R$ is true and $R$ explains $A$ .
According to Faraday's law of electromagnetic induction.
$\int E \cdot d l = \frac{d ϕ}{d t}$
So, $(E)$ is non-conservative field as in conservative field line integral over a closed loop is zero.

Q. Assertion : An emf E is induced in a closed loop where magnetic flux is varied. The induced E is not a conservative field. Reason : The line integral E×dl around the closed loop is nonzero.