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Q. Assertion : An emf $\vec{E}$ is induced in a closed loop where magnetic flux is varied. The induced $\vec{E}$ is not a conservative field.
Reason : The line integral $\vec{E}\times\overrightarrow{dl}$ around the closed loop is nonzero.

AIIMSAIIMS 2006Electromagnetic Induction

Solution:

A and $R$ is true and $R$ explains $A$.
According to Faraday's law of electromagnetic induction.
$\int \vec{ E } \cdot d \vec{ l }=\frac{ d \phi}{ dt }$
So, $( E )$ is non-conservative field as in conservative field line integral over a closed loop is zero.