Assertion (A) Dipole moment of phenol is smaller than that of methanol. Reason (R) In phenol C-O bond is less polar whereas in methanol, C - O bond is more polar.

Question

Assertion (A) Dipole moment of phenol is smaller than that of methanol. Reason (R) In phenol C-O bond is less polar whereas in methanol, C - O bond is more polar. (A) Both A and R are correct; R is the correct explanation of A. (B) Both A and R are correct; R is not the correct explanation of A. (C) A is correct; R is incorrect. (D) R is correct; A is incorrect.

Tardigrade Admin · Accepted Answer

Dipole moment of phenol is smaller than that of methanol because in phenol, Ar group is -I-effect showing group while in methanol - CH 3 is +I-effect group, resulting the greater polarity and hence greater dipole moment of methanol.

Q. Assertion (A) Dipole moment of phenol is smaller than that of methanol.
Reason (R) In phenol $C - O$ bond is less polar whereas in methanol, $C - O$ bond is more polar.

Both A and $R$ are correct; $R$ is the correct explanation of $A$ .

Both A and $R$ are correct; $R$ is not the correct explanation of $A$ .

$A$ is correct; $R$ is incorrect.

$R$ is correct; $A$ is incorrect.

Dipole moment of phenol is smaller than that of methanol because in phenol, $A r$ group is $- I$ -effect showing group while in methanol - $C H_{3}$ is $+ I$ -effect group, resulting the greater polarity and hence greater dipole moment of methanol.

Q. Assertion (A) Dipole moment of phenol is smaller than that of methanol. Reason (R) In phenol C−O bond is less polar whereas in methanol, C−O bond is more polar.

Both A and R are correct; R is the correct explanation of A.

Both A and R are correct; R is not the correct explanation of A.

A is correct; R is incorrect.

R is correct; A is incorrect.