Question

Assertion (A): $8g$ of methane occupies $11.207L$ of volume at $273K$ and $1atm$. pressure.
Reason (R): One mole of any gas at STP occupies $22.414$ litres of volume:
The correct answer is

• A. both A and R are true and R is the correct explanation of A
• B. both A and R are true but R is not the correct explanation of A
• C. A is true but R is false
• D. A is false but R is true

Answer 1

Answer: (A)

One mole of $C{H}_4$ gas is equal to $16g$ of $C{H}_4$
So, at STP $\because 1$ mole or $16g$ of $C{H}_4$
occupies volume $=22.414L$
$\therefore 8g$ of $C{H}_4$ occupies volume
$=\frac{22.414\times 8}{16}=11.207L$
Reason: At STP one mole of a gas occupies $22.414L$ of volume.