As shown in the figure, after passing through the medium 1. The speed of light v2 in medium 2 will be: (. Given c =3 × 108 ms -1 )

Question

As shown in the figure, after passing through the medium 1. The speed of light v2 in medium 2 will be: (. Given c =3 × 108 ms -1 ) (A) 1.0 × 108 ms -1 (B) 0.5 × 108 ms -1 (C) 1.5 × 108 ms -1 (D) 3.0 × 108 ms -1

Tardigrade Admin · Accepted Answer

(μ2/μ text air )=( C / v 2) ∴ (√μ r 2 ε r 2/(1))=( C / v 2) ∴ √(1)(9)=( C / v 2) ∴ v 2=( C /3)

Q. As shown in the figure, after passing through the medium 1. The speed of light $v_{2}$ in medium 2 will be:
$($ Given $c = 3 \times 1 0^{8} m s^{- 1}$ )

$1.0 \times 1 0^{8} m s^{- 1}$

$0.5 \times 1 0^{8} m s^{- 1}$

$1.5 \times 1 0^{8} m s^{- 1}$

$3.0 \times 1 0^{8} m s^{- 1}$

$\frac{μ _{2}}{μ _{air}} = \frac{C}{v _{2}}$
$∴ \frac{μ _{r_{2}} ε _{r_{2}}}{( 1 )} = \frac{C}{v _{2}}$
$∴ (1) (9) = \frac{C}{v _{2}}$
$∴ v_{2} = \frac{C}{3}$

Q. As shown in the figure, after passing through the medium 1. The speed of light v2​ in medium 2 will be: ( Given c=3×108ms−1 )

1.0×108ms−1

0.5×108ms−1

1.5×108ms−1

3.0×108ms−1