Question

As shown in the figure, after passing through the medium 1. The speed of light $v_2$ in medium 2 will be:
$\left(\right.$ Given $c =3 \times 10^8 \,ms ^{-1}$ )

• A. $1.0 \times 10^8 \,ms ^{-1}$
• B. $0.5 \times 10^8 \, ms ^{-1}$
• C. $1.5 \times 10^8 \,ms ^{-1}$
• D. $3.0 \times 10^8 \, ms ^{-1}$

Answer 1

Answer: (A)

$ \frac{\mu_2}{\mu_{\text {air }}}=\frac{ C }{ v _2} $
$ \therefore \frac{\sqrt{\mu_{ r _2} \varepsilon_{ r _2}}}{(1)}=\frac{ C }{ v _2} $
$ \therefore \sqrt{(1)(9)}=\frac{ C }{ v _2} $
$ \therefore v _2=\frac{ C }{3}$