As per Bohr model, the minimum energy (in eV ) required to remove an electron from the ground state of doubly ionized Li atom ( Z=3 ) is

Question

As per Bohr model, the minimum energy (in eV ) required to remove an electron from the ground state of doubly ionized Li atom ( Z=3 ) is (A) 1.51 (B) 13.6 (C) 40.8 (D) 122.4

Tardigrade Admin · Accepted Answer

For hydrogen and hydrogen-like atoms En=-13.6 (( Z 2)/(n2)) eV Therefore, the ground state energy of doubly ionized lithium atom (Z=3,n=1) will be E n=-13⋅ 6((3)2/(1)2)=-122⋅ 4 texte textV ∴ The ionization energy of an electron in the ground state of doubly ionized lithium atom will be 122.4 eV

Q. As per Bohr model, the minimum energy (in $e V$ ) required to remove an electron from the ground state of doubly ionized Li atom ( $Z = 3$ ) is

$1.51$

$13.6$

$40.8$

$122.4$

Q. As per Bohr model, the minimum energy (in eV ) required to remove an electron from the ground state of doubly ionized Li atom ( Z=3 ) is

1.51

13.6

40.8

122.4

For hydrogen and hydrogen-like atoms En​=−13.6(n2)(Z2)​eV Therefore, the ground state energy of doubly ionized lithium atom (Z=3,n=1) will be En​=−13⋅6(1)2(3)2​=−122⋅4eV ∴ The ionization energy of an electron in the ground state of doubly ionized lithium atom will be 122.4 eV

Q. As per Bohr model, the minimum energy (in $e V$ ) required to remove an electron from the ground state of doubly ionized Li atom ( $Z = 3$ ) is

$1.51$

$13.6$

$40.8$

$122.4$