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  4. As per Bohr model, the minimum energy (in eV ) required to remove an electron from the ground state of doubly ionized Li atom ( Z=3 ) is

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Q. As per Bohr model, the minimum energy (in $eV$ ) required to remove an electron from the ground state of doubly ionized Li atom ( $Z=3$ ) is

NTA AbhyasNTA Abhyas 2022

Solution:

For hydrogen and hydrogen-like atoms
$E_n=-13.6 \frac{\left( Z ^2\right)}{\left(n^2\right)} eV$
Therefore, the ground state energy of doubly ionized lithium atom (Z=3,n=1) will be
$E _{n}=-13\cdot 6\frac{\left(3\right)^{2}}{\left(1\right)^{2}}=-122\cdot 4\text{e}\text{V}$
$\therefore $ The ionization energy of an electron in the ground state of doubly ionized lithium atom will be 122.4 eV