Question

As a body performs S.H.M., its potential energy $U$ varies with time $t$ as indicated in

• A.
• B.
• C.
• D.

Answer 1

Answer: (A)

Potential energy $=\frac{1}{2}k{x}^2=\frac{1}{2}{A}^2{\omega }^2{\sin }^2(\omega t+\varphi )$
The graph for ${\sin }^2(\omega t+\varphi )$ is given by (1).