Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. As a body performs S.H.M., its potential energy $U$ varies with time $t$ as indicated in

Oscillations

Solution:

Potential energy $=\frac{1}{2} k x^{2}=\frac{1}{2} A^{2} \omega^{2} \sin ^{2}(\omega t+\phi)$
The graph for $\sin ^{2}(\omega t+\phi)$ is given by (1).