Arrange the group 15 hydrides in the increasing order of H -M -H bond angle.

Question

Arrange the group 15 hydrides in the increasing order of H -M -H bond angle. (A) SbH3 < AsH3 < PH3 < NH3 (B) NH3 < PH3 < AsH3 < SbH3 (C) NH3 < SbH3 < AsH3 < PH3 (D) NH3 < PH3 < SbH3 < AsH3

Tardigrade Admin · Accepted Answer

Bond angle of group 15 hydrides is in order of underset91.3°SbH3< underset91.8°AsH3< underset93.8°PH3< underset107.2°NH3

Q. Arrange the group $15$ hydrides in the increasing order of $H - M - H$ bond angle.

$S b H_{3} < A s H_{3} < P H_{3} < N H_{3}$

$N H_{3} < P H_{3} < A s H_{3} < S b H_{3}$

$N H_{3} < S b H_{3} < A s H_{3} < P H_{3}$

$N H_{3} < P H_{3} < S b H_{3} < A s H_{3}$

Bond angle of group $15$ hydrides is in order of
$91. 3^{\circ} S b H_{3} < 91. 8^{\circ} A s H_{3} < 93. 8^{\circ} P H_{3} < 107. 2^{\circ} N H_{3}$

Q. Arrange the group 15 hydrides in the increasing order of H−M−H bond angle.

SbH3​<AsH3​<PH3​<NH3​

NH3​<PH3​<AsH3​<SbH3​

NH3​<SbH3​<AsH3​<PH3​

NH3​<PH3​<SbH3​<AsH3​