Question

Arrange the group $15$ hydrides in the increasing order of $H -M -H$ bond angle.

• A. $SbH_{3} <\,AsH_{3} <\, PH_{3} <\, NH_{3}$
• B. $NH_{3} <\, PH_{3} <\, AsH_{3} <\, SbH_{3}$
• C. $NH_{3} <\, SbH_{3} < \,AsH_{3} <\, PH_{3}$
• D. $NH_{3} <\, PH_{3} <\, SbH_{3} <\, AsH_{3}$

Answer 1

Answer: (A)

Bond angle of group $15$ hydrides is in order of
$\underset{91.3^{\circ}}{SbH_{3}}<\, \underset{91.8^{\circ}}{AsH_{3}}<\,\underset{93.8^{\circ}}{PH_{3}}<\,\underset{107.2^{\circ}}{NH_{3}}$