Arrange the following orbitals in decreasing order of energy. A. n=3, l =0, m =0 B. n =4, l =0, m =0 C. n =3, l =1, m =0 D. n =3, l =2, m =1 The correct option for the order is :

Question

Arrange the following orbitals in decreasing order of energy. A. n=3, l =0, m =0 B. n =4, l =0, m =0 C. n =3, l =1, m =0 D. n =3, l =2, m =1 The correct option for the order is : (A) D > B > C > A (B) B > D > C > A (C) A > C > B > D (D) D > B > A > C

Tardigrade Admin · Accepted Answer

(A) n =3 ; l =0 ; m =0 ; 3 s orbital (B) n =4 ; l =0 ; m =0 ; 4 s orbital (C) n =3 ; l =1 ; m =0 ; 3 p orbital (D) n =3 ; l =2 ; m =0 ; 3 d orbital As per Hund's rule energy is given by ( n +l) value. If value of ( n +l) remains same then energy is given by n only.

Q. Arrange the following orbitals in decreasing order of energy.
A. $n = 3, l = 0, m = 0$
B. $n = 4, l = 0, m = 0$
C. $n = 3, l = 1, m = 0$
D. $n = 3, l = 2, m = 1$
The correct option for the order is :

$D > B > C > A$

$B > D > C > A$

$A > C > B > D$

$D > B > A > C$

(A) $n = 3; l = 0; m = 0; 3 s$ orbital
(B) $n = 4; l = 0; m = 0; 4 s$ orbital
(C) $n = 3; l = 1; m = 0; 3 p$ orbital
(D) $n = 3; l = 2; m = 0; 3 d$ orbital
As per Hund's rule energy is given by $(n + l)$ value. If value of $(n + l)$ remains same then energy is given by n only.

Q. Arrange the following orbitals in decreasing order of energy. A. n=3,l=0,m=0 B. n=4,l=0,m=0 C. n=3,l=1,m=0 D. n=3,l=2,m=1 The correct option for the order is :

D>B>C>A

B>D>C>A

A>C>B>D

D>B>A>C