Question

Arrange the following orbitals in decreasing order of energy.
A. $n=3, l =0, m =0$
B. $n =4, l =0, m =0$
C. $n =3, l =1, m =0$
D. $n =3, l =2, m =1$
The correct option for the order is :

• A. $D > B > C > A$
• B. $B > D > C > A$
• C. $A > C > B > D$
• D. $D > B > A > C$

Answer 1

Answer: (A)

(A) $n =3 ; l =0 ; m =0 ; 3 s$ orbital
(B) $n =4 ; l =0 ; m =0 ; 4 s$ orbital
(C) $n =3 ; l =1 ; m =0 ; 3 p$ orbital
(D) $n =3 ; l =2 ; m =0 ; 3 d$ orbital
As per Hund's rule energy is given by $( n +l)$ value. If value of $( n +l)$ remains same then energy is given by n only.