1. Tardigrade
  2. Question
  3. Chemistry
  4. Arrange the following orbitals in decreasing order of energy. A. n=3, l =0, m =0 B. n =4, l =0, m =0 C. n =3, l =1, m =0 D. n =3, l =2, m =1 The correct option for the order is :

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Q. Arrange the following orbitals in decreasing order of energy.
A. $n=3, l =0, m =0$
B. $n =4, l =0, m =0$
C. $n =3, l =1, m =0$
D. $n =3, l =2, m =1$
The correct option for the order is :

JEE MainJEE Main 2023Structure of Atom

Solution:

(A) $n =3 ; l =0 ; m =0 ; 3 s$ orbital
(B) $n =4 ; l =0 ; m =0 ; 4 s$ orbital
(C) $n =3 ; l =1 ; m =0 ; 3 p$ orbital
(D) $n =3 ; l =2 ; m =0 ; 3 d$ orbital
As per Hund's rule energy is given by $( n +l)$ value. If value of $( n +l)$ remains same then energy is given by n only.