Arrange the following monomers in order of decreasing ability to undergo cationic polymerisation. (I) CH2 = CH -C6H4(NO2) (II) CH2 = CH -C6H4(CH3) (III) CH2 = CH -C6H4(OCH3)

Question

Arrange the following monomers in order of decreasing ability to undergo cationic polymerisation. (I) CH2 = CH -C6H4(NO2) (II) CH2 = CH -C6H4(CH3) (III) CH2 = CH -C6H4(OCH3) (A) I > II > III (B)  II > I > III (C) III > II > I (D) I > III > II

Tardigrade Admin · Accepted Answer

More stable is carbocation more is ability to undergo cationic polymerisation. +I and +R nature of -OCH3 stabilizes carbocation.

Q. Arrange the following monomers in order of decreasing ability to undergo cationic polymerisation.
(I) $C H_{2} = C H - C_{6} H_{4} (N O_{2})$
(II) $C H_{2} = C H - C_{6} H_{4} (C H_{3})$
(III) $C H_{2} = C H - C_{6} H_{4} (OC H_{3})$

$I > II > III$

$II > I > III$

$III > II > I$

$I > III > II$

More stable is carbocation more is ability to undergo cationic polymerisation.
$+ I$ and $+ R$ nature of $- OC H_{3}$ stabilizes carbocation.

Q. Arrange the following monomers in order of decreasing ability to undergo cationic polymerisation. (I) CH2​=CH−C6​H4​(NO2​) (II) CH2​=CH−C6​H4​(CH3​) (III) CH2​=CH−C6​H4​(OCH3​)

I>II>III

II>I>III

III>II>I

I>III>II