1. Tardigrade
  2. Question
  3. Chemistry
  4. Arrange the following monomers in order of decreasing ability to undergo cationic polymerisation. (I) CH2 = CH -C6H4(NO2) (II) CH2 = CH -C6H4(CH3) (III) CH2 = CH -C6H4(OCH3)

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Q. Arrange the following monomers in order of decreasing ability to undergo cationic polymerisation.
(I) $CH_{2} = CH -C_{6}H_{4}\left(NO_{2}\right)$
(II) $CH_{2} = CH -C_{6}H_{4}\left(CH_3\right)$
(III) $CH_{2} = CH -C_{6}H_{4}\left(OCH_{3}\right)$

Polymers

Solution:

More stable is carbocation more is ability to undergo cationic polymerisation.
$+I$ and $+R$ nature of $-OCH_{3}$ stabilizes carbocation.