Arrange the following molecules from most to least polar.

Question

Arrange the following molecules from most to least polar. <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/c-jdr9af715ullrtas.jpg" /> (A) III > V > II > I = IV (B) II > IV > III > IV > I (C) III > II > V > IV > I (D) V > III > II > IV = I

Tardigrade Admin · Accepted Answer

(i) textlnCH4 and CCl 4 being tetrahedral (symmetrical molecules), bond dipoles cancel one other resulting in zero dipole moment. (ii) As electronegativity difference between two bonded atoms increases, the bond polarity increases resulting into the increase in dipole moment. C - F bond has less dipole moment than C - Cl bond as the F is smaller. The overall dipole moment is CF 2 H 2> CH 2 Cl 2> CF 2 Cl 2> CH 4= CCl 4

Q. Arrange the following molecules from most to least polar.

III > V > II > I = IV

II > IV > III > IV > I

III > II > V > IV > I

V > III > II > IV = I