Arrange the following in the order of increasing mass (atomic mass O=16,Cu=63, N=14 ) I. One atom of oxygen II. One atom of nitrogen III. 1 × 10-10 mole of oxygen IV. 1 × 10-10 mole of copper

Question

Arrange the following in the order of increasing mass (atomic mass O=16,Cu=63, N=14 ) I. One atom of oxygen II. One atom of nitrogen III. 1 × 10-10 mole of oxygen IV. 1 × 10-10 mole of copper (A) II < I < III < IV (B) I < II < III < IV (C) III < II < IV < I (D) IV < II < III < I

Tardigrade Admin · Accepted Answer

I. One atom of oxygen =16× 1.66× 10-24g II. One atom of nitrogen =14× 1.66× 10-24g III. 1× 10-10 mole of oxygen =32× 1× 10-10g IV. 1× 10-10 mole of copper =63× 1× 10-10g Thus, the correct order of increasing mass II < I < III < IV

Q. Arrange the following in the order of increasing mass (atomic mass $O = 16, C u = 63,$ $N = 14$ )
I. One atom of oxygen
II. One atom of nitrogen
III. $1 \times 1 0^{- 10}$ mole of oxygen
IV. $1 \times 1 0^{- 10}$ mole of copper

$II < I < III < I V$

$I < II < III < I V$

$III < II < I V < I$

$I V < II < III < I$

$II < I V < I < III$

Q. Arrange the following in the order of increasing mass (atomic mass O=16,Cu=63, N=14 ) I. One atom of oxygen II. One atom of nitrogen III. 1×10−10 mole of oxygen IV. 1×10−10 mole of copper

II<I<III<IV

I<II<III<IV

III<II<IV<I

IV<II<III<I

II<IV<I<III