Arrange the following in order of decreasing N - O bond length: NO2+, NO2-, NO3-

Question

Arrange the following in order of decreasing N - O bond length: NO2+, NO2-, NO3- (A) NO-3 > NO+2 > NO-2 (B) NO-3 > NO-2 > NO+2 (C) NO+2 > NO-3 > NO-2 (D) NO-3 > NO-3 > NO+2

Tardigrade Admin · Accepted Answer

N atom in NO2 is sp hybridised while in NO-2 and NO-3, it is sp2 hybridised. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/6a7fff7374e92de7a62ad27818c4c752-.png" /> Bond order propto (1/ textBond Length) So. Bond length order is NO-3 > NO-2 > NO-2

Q. Arrange the following in order of decreasing $N - O$ bond length: $N O_{2}^{+}, N O_{2}^{-}, N O_{3}^{-}$

$N O_{3}^{-} > N O_{2}^{+} > N O_{2}^{-}$

$N O_{3}^{-} > N O_{2}^{-} > N O_{2}^{+}$

$N O_{2}^{+} > N O_{3}^{-} > N O_{2}^{-}$

$N O_{3}^{-} > N O_{3}^{-} > N O_{2}^{+}$

$N$ atom in $N O_{2}$ is $s p$ hybridised while in $N O_{2}^{-}$ and $N O_{3}^{-}$ , it is $s p^{2}$ hybridised.

Bond order $\propto \frac{1}{Bond Length}$
So. Bond length order is $N O_{3}^{-} > N O_{2}^{-} > N O_{2}^{-}$

Q. Arrange the following in order of decreasing N−O bond length: NO2+​,NO2−​,NO3−​

NO3−​>NO2+​>NO2−​

NO3−​>NO2−​>NO2+​

NO2+​>NO3−​>NO2−​

NO3−​>NO3−​>NO2+​