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  4. Arrange the following in order of decreasing N - O bond length: NO2+, NO2-, NO3-

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Q. Arrange the following in order of decreasing $N - O$ bond length: $NO_2^+, NO_2^-, NO_3^-$

Chemical Bonding and Molecular Structure

Solution:

$N$ atom in $NO_2$ is $sp$ hybridised while in $NO^-_2$ and $NO^-_3$, it is $sp^2$ hybridised.
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Bond order $\propto \frac{1}{\text{Bond Length}}$
So. Bond length order is $NO^-_3 > NO^-_2 > NO^-_2$