Arrange the following compounds in order of increasing dipole moment: (I) Toluene (II) m -Dichlorobenzene (III) o -Dichlorobenzene (IV) p -Dichlorobenzene

Question

Arrange the following compounds in order of increasing dipole moment: (I) Toluene (II) m -Dichlorobenzene (III) o -Dichlorobenzene (IV) p -Dichlorobenzene (A) I < IV < II < III (B) IV < I < II < III (C) IV < I < III < II (D) IV < II < I < III

Tardigrade Admin · Accepted Answer

o-, m-, p - derivatives have α=60°, 120° and 180° respectively, p -derivative has zero dipole moment. Dipole moment of m -dichlorobenzene is more than toluene.

Q. Arrange the following compounds in order of increasing dipole moment :
(I) Toluene
(II) $m$ -Dichlorobenzene
(III) $o$ -Dichlorobenzene
(IV) $p$ -Dichlorobenzene

$I < I V < II < III$

$I V < I < II < III$

$I V < I < III < II$

$I V < II < I < III$

$o -, m -, p$ - derivatives have $α = 6 0^{\circ}, 12 0^{\circ}$ and $18 0^{\circ}$ respectively, $p$ -derivative has zero dipole moment. Dipole moment of $m$ -dichlorobenzene is more than toluene.

Q. Arrange the following compounds in order of increasing dipole moment : (I) Toluene (II) m -Dichlorobenzene (III) o -Dichlorobenzene (IV) p -Dichlorobenzene

I<IV<II<III

IV<I<II<III

IV<I<III<II

IV<II<I<III