Arrange the following complexes in increasing order of conductivity of their solutions. (i) [Co(NH3)3Cl3] (ii) [Co(NH3)4Cl2]Cl (iii) [Co(NH3)6]Cl3 (iv) [Co(NH3)5Cl] Cl2

Question

Arrange the following complexes in increasing order of conductivity of their solutions. (i) [Co(NH3)3Cl3] (ii) [Co(NH3)4Cl2]Cl (iii) [Co(NH3)6]Cl3 (iv) [Co(NH3)5Cl] Cl2 (A) (i) < (ii) < (iv) < (iii) (B) (ii) < (i) < (iii) < (iv) (C) (i) < (iii) < (ii) < (iv) (D) (iv) < (i) < (ii) < (iii)

Tardigrade Admin · Accepted Answer

Higher the number of ions in the solution, higher is the conductivity. No. of ions: [Co(NH3)3 Cl3]=0 ; [Co(NH3)4Cl2] Cl=2 [Co(NH3)5Cl] Cl2=3 ; [Co(NH3)6]Cl3=4

Q. Arrange the following complexes in increasing order of conductivity of their solutions.
(i) $[C o (N H_{3})_{3} C l_{3}]$
(ii) $[C o (N H_{3})_{4} C l_{2}] Cl$
(iii) $[C o (N H_{3})_{6}] C l_{3}$
(iv) $[C o (N H_{3})_{5} Cl] C l_{2}$

$(i) < (ii) < (i v) < (iii)$

$(ii) < (i) < (iii) < (i v)$

$(i) < (iii) < (ii) < (i v)$

$(i v) < (i) < (ii) < (iii)$

Higher the number of ions in the solution, higher is the conductivity.
No. of ions : $[C o (N H_{3})_{3} C l_{3}] = 0; [C o (N H_{3})_{4} C l_{2}] Cl = 2$
$[C o (N H_{3})_{5} Cl] C l_{2} = 3; [C o (N H_{3})_{6}] C l_{3} = 4$

Q. Arrange the following complexes in increasing order of conductivity of their solutions. (i) [Co(NH3​)3​Cl3​] (ii) [Co(NH3​)4​Cl2​]Cl (iii) [Co(NH3​)6​]Cl3​ (iv) [Co(NH3​)5​Cl]Cl2​

(i)<(ii)<(iv)<(iii)

(ii)<(i)<(iii)<(iv)

(i)<(iii)<(ii)<(iv)

(iv)<(i)<(ii)<(iii)