Question

Arrange the following complexes in increasing order of conductivity of their solutions.
(i) $ [Co(NH_{3})_{3}Cl_{3}]$
(ii) $[Co(NH_{3})_{4}Cl_{2}]Cl$
(iii) $[Co(NH_{3})_{6}]Cl_{3}$
(iv) $[Co(NH_{3})_{5}Cl] Cl_{2}$

• A. $(i) <\, (ii) <\, (iv) < \,(iii)$
• B. $(ii) <\, (i) < \,(iii) <\, (iv)$
• C. $(i) <\, (iii) <\, (ii) <\, (iv)$
• D. $(iv) <\, (i) <\, (ii) < \,(iii)$

Answer 1

Answer: (A)

Higher the number of ions in the solution, higher is the conductivity.
No. of ions : $[Co(NH_{3})_{3} Cl_{3}]=0 ; [Co(NH_{3})_{4}Cl_{2}] Cl=2$
$[Co(NH_{3})_{5}Cl] Cl_{2}=3 ; [Co(NH_{3})_{6}]Cl_{3}=4$