Arrange the following alkyl halides in decreasing order of the rate of β-elimination reaction with alcoholic KOH.

Question

Arrange the following alkyl halides in decreasing order of the rate of β-elimination reaction with alcoholic KOH. (A) I > II > III (B) III > II > I (C) II > III > I (D) I > III > II

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/30567a2ec8b28d9a4e7e145fbcb1ce82-.jpeg" /> More the number of β-substituents (alkyl groups), more stable alkene it will form on β-elimination and more will be the reactivity. Thus, the decreasing order of the rate of β-elimination reaction with alcoholic KOH is: I > III > II

Q. Arrange the following alkyl halides in decreasing order of the rate of $β$ -elimination reaction with alcoholic $K O H$ .

$I > II > III$

$III > II > I$

$II > III > I$

$I > III > II$

More the number of $β$ -substituents (alkyl groups), more stable alkene it will form on $β$ -elimination and more will be the reactivity. Thus, the decreasing order of the rate of $β$ -elimination reaction with alcoholic $K O H$ is :
$I > III > II$

Q. Arrange the following alkyl halides in decreasing order of the rate of β-elimination reaction with alcoholic KOH.

I>II>III

III>II>I

II>III>I

I>III>II