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  4. Arrange the following alkyl halides in decreasing order of the rate of β-elimination reaction with alcoholic KOH.

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Q. Arrange the following alkyl halides in decreasing order of the rate of $\beta$-elimination reaction with alcoholic $KOH$.Chemistry Question Image

Hydrocarbons

Solution:

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More the number of $\beta$-substituents (alkyl groups), more stable alkene it will form on $\beta$-elimination and more will be the reactivity. Thus, the decreasing order of the rate of $\beta$-elimination reaction with alcoholic $KOH$ is :
$I > III > II$