Aqueous solutions of two compounds M-O-H and M'-O-H have been prepared in two different beakers. If the electronegativity of M = 3.5, M' = 1.72, O = 3.0 and H = 2.1, then the solutions respectively are

Question

Aqueous solutions of two compounds M-O-H and M'-O-H have been prepared in two different beakers. If the electronegativity of M = 3.5, M' = 1.72, O = 3.0 and H = 2.1, then the solutions respectively are (A) acidic, acidic (B) acidic, basic (C) basic, basic (D) basic, acidic.

Tardigrade Admin · Accepted Answer

In the compound M - O - H, if IE or E.N. of M is low, the compound will act as a base and if the IE or E.N. of M is high, the compound will behave as an acid. Therefore, M - O - H will act as an acid as E.N. of M is high (3.5) and M' - O - H will act as a base as E.N. of M' is low (1.72).

Q. Aqueous solutions of two compounds M−O−H and M′−O−H have been prepared in two different beakers. If the electronegativity of M=3.5, M′=1.72, O=3.0 and H=2.1, then the solutions respectively are

acidic, acidic

acidic, basic

basic, basic

basic, acidic.

In the compound M - O - H, if IE or E.N. of M is low, the compound will act as a base and if the IE or E.N. of M is high, the compound will behave as an acid. Therefore, M - O - H will act as an acid as E.N. of M is high (3.5) and M' - O - H will act as a base as E.N. of M' is low (1.72).

Q. Aqueous solutions of two compounds $M - O - H$ and $M^{'} - O - H$ have been prepared in two different beakers. If the electronegativity of $M = 3.5$ , $M^{'} = 1.72$ , $O = 3.0$ and $H = 2.1$ , then the solutions respectively are