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Q. Aqueous solutions of two compounds $M-O-H$ and $M'-O-H$ have been prepared in two different beakers. If the electronegativity of $M = 3.5$, $M' = 1.72$, $O = 3.0$ and $H = 2.1$, then the solutions respectively are

Classification of Elements and Periodicity in Properties

Solution:

In the compound M - O - H, if IE or E.N. of M is low, the compound will act as a base and if the IE or E.N. of M is high, the compound will behave as an acid. Therefore, M - O - H will act as an acid as E.N. of M is high (3.5) and M' - O - H will act as a base as E.N. of M' is low (1.72).