Aniline reacts with excess Br2/H2O to give the major product.

Question

Aniline reacts with excess Br2/H2O to give the major product. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Aniline reacts with excess Br2/H2O to give 2, 4, 6- tribromoaniline as a major product. The NH2 group attached to benzene ring makes it more activating and occupy all the ortho and para positions. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/6d906ba4928df97da22f44a4f15d7a6b-.png" />

Q. Aniline reacts with excess $B r_{2} / H_{2} O$ to give the major product.

Aniline reacts with excess $B r_{2} / H_{2} O$ to give $2, 4, 6 -$ tribromoaniline as a major product. The $N H_{2}$ group attached to benzene ring makes it more activating and occupy all the ortho and para positions.

Q. Aniline reacts with excess Br2​/H2​O to give the major product.

Aniline reacts with excess Br2​/H2​O to give 2,4,6− tribromoaniline as a major product. The NH2​ group attached to benzene ring makes it more activating and occupy all the ortho and para positions.

Q. Aniline reacts with excess $B r_{2} / H_{2} O$ to give the major product.

Aniline reacts with excess $B r_{2} / H_{2} O$ to give $2, 4, 6 -$ tribromoaniline as a major product. The $N H_{2}$ group attached to benzene ring makes it more activating and occupy all the ortho and para positions.