An unopened soda has an aqueous concentration of CO2 at 25°C equal to 0.0408 molal. Thus, pressure of CO2 gas in the can is (KH = 0.034 mol/kg bar)

Question

An unopened soda has an aqueous concentration of CO2 at 25°C equal to 0.0408 molal. Thus, pressure of CO2 gas in the can is (KH = 0.034 mol/kg bar) (A) 0.671 bar (B) 1.49 bar (C) 1.41 bar (D) 1.71 bar

Tardigrade Admin · Accepted Answer

Solubility =KHρCO2 ∴ ρCO2=( textSolubility/KH) =(0.0408 mol kg-1/0.034 mol kg-1 bar-1) =1.411 bar Note: If KH is in the unit of pressure, then, Concentration × KH = pressure If KH is in the unit of text(pressure)-1, then Concentration =KH× pressure

Q. An unopened soda has an aqueous concentration of CO2​ at 25∘C equal to 0.0408 molal. Thus, pressure of CO2​ gas in the can is (KH​=0.034mol/kg bar)

0.671 bar

1.49 bar

1.41 bar

1.71 bar

Solubility =KHρCO2​​​ ∴ρCO2​​=KH​Solubility​ =0.034molkg−1bar−10.0408molkg−1​ =1.411 bar Note : If KH​ is in the unit of pressure, then, Concentration ×KH​ = pressure If KH​ is in the unit of (pressure)−1, then Concentration =KH​× pressure

Q. An unopened soda has an aqueous concentration of $C O_{2}$ at $2 5^{\circ} C$ equal to 0.0408 molal. Thus, pressure of $C O_{2}$ gas in the can is $(K_{H} = 0.034 m o l / k g$ bar)