An unknown compound has molecular weight 92 and on acetylation its molecular weight becomes 218. Number of ‘OH’ groups present in unknown compound are

Question

An unknown compound has molecular weight 92 and on acetylation its molecular weight becomes 218. Number of ‘OH’ groups present in unknown compound are (A) 2 (B) 3 (C) 4 (D) 1

Tardigrade Admin · Accepted Answer

Increase in mol. wt =218-92=126 Molar mass of one CH 3 CO groups =43 Number of acyl group or OH group in unknown compound =(126/43)=3 (approx.)

Q. An unknown compound has molecular weight $92$ and on acetylation its molecular weight becomes $218$ . Number of ‘ $O H$ ’ groups present in unknown compound are

2

3

4

1

Increase in mol. wt $= 218 - 92 = 126$
Molar mass of one $C H_{3} CO$ groups $= 43$
Number of acyl group or
$O H$ group in unknown compound $= \frac{126}{43} = 3$ (approx.)

Q. An unknown compound has molecular weight 92 and on acetylation its molecular weight becomes 218. Number of ‘OH’ groups present in unknown compound are

2

3

4

1

Increase in mol. wt =218−92=126 Molar mass of one CH3​CO groups =43 Number of acyl group or OH group in unknown compound =43126​=3 (approx.)

Q. An unknown compound has molecular weight $92$ and on acetylation its molecular weight becomes $218$ . Number of ‘ $O H$ ’ groups present in unknown compound are

Increase in mol. wt $= 218 - 92 = 126$
Molar mass of one $C H_{3} CO$ groups $= 43$
Number of acyl group or
$O H$ group in unknown compound $= \frac{126}{43} = 3$ (approx.)