Question

An organic compound contains $24\%$ carbon, $4\%$ hydrogen and remaining chlorine. Its empirical formula is

• A. $CHCl$
• B. $C{H}_{2}Cl$
• C. $CHC{l}_2$
• D. $C{H}_{3}Cl$
• E. $C{H}_{2}C{l}_2$

Answer 1

Answer: (B)

Percentage	No.of moles	Atomic ratio
$C=24\%$	$\frac{24}{12}=2$	$\frac{2}{2}=1$
$H=4\%$	$\frac{4}{1}=4$	$\frac{4}{2}=2$
$Cl72\%$	$\frac{72}{35.5}=2$	$\frac{2}{2}=1$

E.F. $=C{H}_{2}Cl$