An organic compound (.A.) contains 20 %C,46.66 %N and 6.66 %H . It gave NH3 gas on heating with NaOH . The organic compound (.A.) could be:

Question

An organic compound (.A.) contains 20 %C,46.66 %N and 6.66 %H . It gave NH3 gas on heating with NaOH . The organic compound (.A.) could be: (A) CH3CONH2 (B) C6H5CONH2 (C) NH2CONH2 (D) CH3NHCONH2

Tardigrade Admin · Accepted Answer

C=(20/12)=1.66=1 N=(46.66/14)=3.33=2 H=(6.66/1)=6.66=4 O=( 26.68/16)=1.66=1 Empirical formula of compound CN2H4O Since, this organic compound contains carbon, hydrogen, nitrogen and oxygen and on heating with alkali liberates NH3 the organic compound must be urea. NH2CONH2+2NaOH arrow 2NH3+Na2CO3

Q. An organic compound $(A)$ contains $20% C, 46.66% N$ and $6.66% H$ . It gave $N H_{3}$ gas on heating with $N a O H$ . The organic compound $(A)$ could be:

$C H_{3} CON H_{2}$

$C_{6} H_{5} CON H_{2}$

$N H_{2} CON H_{2}$

$C H_{3} N H CON H_{2}$

Q. An organic compound (A) contains 20%C,46.66%N and 6.66%H . It gave NH3​ gas on heating with NaOH . The organic compound (A) could be:

CH3​CONH2​

C6​H5​CONH2​

NH2​CONH2​

CH3​NHCONH2​

Q. An organic compound $(A)$ contains $20% C, 46.66% N$ and $6.66% H$ . It gave $N H_{3}$ gas on heating with $N a O H$ . The organic compound $(A)$ could be:

$C H_{3} CON H_{2}$

$C_{6} H_{5} CON H_{2}$

$N H_{2} CON H_{2}$

$C H_{3} N H CON H_{2}$