An optically active organic compound has molecular formula C5H12O(X). X on oxidation with CrO3/H2SO4 gives an achiral C5H10O. Hence, X could be

Question

An optically active organic compound has molecular formula C5H12O(X). X on oxidation with CrO3/H2SO4 gives an achiral C5H10O. Hence, X could be (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Oxidation of X giving ketone as well as X is chiral, it must be a secondary alcohol with α-chiral carbon. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/8101ceaba2f0986eb0881df84c6da403-.png" />

Q. An optically active organic compound has molecular formula $C_{5} H_{12} O (X) . X$ on oxidation with $C r O_{3} / H_{2} S O_{4}$ gives an achiral $C_{5} H_{10} O .$ Hence, $X$ could be

Oxidation of $X$ giving ketone as well as $X$ is chiral, it must be a secondary alcohol with $α$ -chiral carbon.

Q. An optically active organic compound has molecular formula C5​H12​O(X).X on oxidation with CrO3​/H2​SO4​ gives an achiral C5​H10​O. Hence, X could be

Oxidation of X giving ketone as well as X is chiral, it must be a secondary alcohol with α-chiral carbon.

Q. An optically active organic compound has molecular formula $C_{5} H_{12} O (X) . X$ on oxidation with $C r O_{3} / H_{2} S O_{4}$ gives an achiral $C_{5} H_{10} O .$ Hence, $X$ could be

Oxidation of $X$ giving ketone as well as $X$ is chiral, it must be a secondary alcohol with $α$ -chiral carbon.