1. Tardigrade
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  3. Chemistry
  4. An optically active organic compound has molecular formula C5H12O(X). X on oxidation with CrO3/H2SO4 gives an achiral C5H10O. Hence, X could be

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Q. An optically active organic compound has molecular formula $C_5H_{12}O\left(X\right). X$ on oxidation with $CrO_3/H_2SO_4$ gives an achiral $C_5H_{10}O.$ Hence, $X$ could be

Aldehydes Ketones and Carboxylic Acids

Solution:

Oxidation of $X$ giving ketone as well as $X$ is chiral, it must be a secondary alcohol with $\alpha$-chiral carbon.
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