An optically active carboxylic acid X has the molecular formula C 6 H 10 O 2 and can be shown by chemical and physical tests to contain the group - CH = CH 2 and atleast one - CH 3 group. When X is reduced with hydrogen over platinum, the product formed is optically inactive. Which of the following best represents the structure of X ?

Question

An optically active carboxylic acid X has the molecular formula C 6 H 10 O 2 and can be shown by chemical and physical tests to contain the group - CH = CH 2 and atleast one - CH 3 group. When X is reduced with hydrogen over platinum, the product formed is optically inactive. Which of the following best represents the structure of X ? (A) CH 2= CH - CH ( CH 3)- CH 2- COOH (B) CH 2= CH - CH ( CH 2 CH 3)- COOH (C) CH 2= CH - CH 2- CH ( CH 3)- COOH (D) CH 2= CH - C ( CH 3)2- COOH

Tardigrade Admin · Accepted Answer

Correct answer is (b) CH 2= CH - CH ( CH 2 CH 3)- COOH

$C H_{2} = C H - C H (C H_{3}) - C H_{2} - COO H$

$C H_{2} = C H - C H (C H_{2} C H_{3}) - COO H$

$C H_{2} = C H - C H_{2} - C H (C H_{3}) - COO H$

$C H_{2} = C H - C (C H_{3})_{2} - COO H$

Correct answer is (b) $C H_{2} = C H - C H (C H_{2} C H_{3}) - COO H$

CH2​=CH−CH(CH3​)−CH2​−COOH

CH2​=CH−CH(CH2​CH3​)−COOH

CH2​=CH−CH2​−CH(CH3​)−COOH

CH2​=CH−C(CH3​)2​−COOH

Correct answer is (b) CH2​=CH−CH(CH2​CH3​)−COOH

$C H_{2} = C H - C H (C H_{3}) - C H_{2} - COO H$

$C H_{2} = C H - C H (C H_{2} C H_{3}) - COO H$

$C H_{2} = C H - C H_{2} - C H (C H_{3}) - COO H$

$C H_{2} = C H - C (C H_{3})_{2} - COO H$

Correct answer is (b) $C H_{2} = C H - C H (C H_{2} C H_{3}) - COO H$