An open manometer attached to a flask containing ammonia gas have no difference in mercury level initially as shown in diagram. After sparking into the flask, ammonia is partially dissociated as 2 mathrmNH3( mathrm~g) longrightarrow mathrmN2( mathrm~g)+3 mathrmH2( mathrm~g) . Now it have difference of text18 textcm in mercury level in two columns, what is partial pressure of mathrmH2( mathrm~g) at equilibrium ?

Question

An open manometer attached to a flask containing ammonia gas have no difference in mercury level initially as shown in diagram. After sparking into the flask, ammonia is partially dissociated as 2 mathrmNH3( mathrm~g) longrightarrow mathrmN2( mathrm~g)+3 mathrmH2( mathrm~g) . Now it have difference of text18 textcm in mercury level in two columns, what is partial pressure of mathrmH2( mathrm~g) at equilibrium ? <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/c-pnwzlcbmtglb.png" /> (A)  text9 textcm of textHg (B)  text18 cm of textHg (C)  text27 textcm of textHg (D) None of these

Tardigrade Admin · Accepted Answer

underset76-2x2NH3(g) → undersetxN2(g)+ underset3x3H2 7 6 + 2 textx = 7 6 + 1 8 2 textx = 1 8 ∴ textx = 9 ∴ textp textH2 = 3 × 9 = text 27 cm of Hg

$9 cm$ of $Hg$

$18 cm$ of $Hg$

$27 cm$ of $Hg$

None of these

$76 - 2 x 2 N H_{3} (g) \to x N_{2} (g) + 3 x 3 H_{2}$
$76 + 2 x = 76 + 18$

$2 x = 18$

$∴ x = 9$

$∴ p_{H_{2}} = 3 \times 9$

$= 27 cm of Hg$

9cm of Hg

18 cm of Hg

27cm of Hg

None of these

76−2x2NH3​(g)​→xN2​(g)​+3x3H2​​ 76+2x=76+18 2x=18 ∴x=9 ∴pH2​​=3×9 = 27 cm of Hg

$9 cm$ of $Hg$

$18 cm$ of $Hg$

$27 cm$ of $Hg$

$76 - 2 x 2 N H_{3} (g) \to x N_{2} (g) + 3 x 3 H_{2}$
$76 + 2 x = 76 + 18$

$2 x = 18$

$∴ x = 9$

$∴ p_{H_{2}} = 3 \times 9$

$= 27 cm of Hg$