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Q. An open manometer attached to a flask containing ammonia gas have no difference in mercury level initially as shown in diagram. After sparking into the flask, ammonia is partially dissociated as $2 \mathrm{NH}_3(\mathrm{~g}) \longrightarrow \mathrm{N}_2(\mathrm{~g})+3 \mathrm{H}_2(\mathrm{~g})$ . Now it have difference of $\text{18} \, \text{cm}$ in mercury level in two columns, what is partial pressure of $\mathrm{H}_2(\mathrm{~g})$ at equilibrium ?

Question

NTA AbhyasNTA Abhyas 2020States of Matter

Solution:

$\underset{76-2x}{2NH_{3}(g)} \to \underset{x}{N_{2}(g)}+\underset{3x}{3H_{2}}$
$7 6 + 2 \text{x} = 7 6 + 1 8$

$2 \text{x} = 1 8$

$∴ \, \, \text{x} = 9$

$∴ \, \text{p}_{\text{H}_{2}} = 3 \times 9$

$= \text{ 27 cm of Hg}$