An object of mass m moves with constant speed in a circular path of radius R under the action of a force of constant magnitude F. The kinetic energy of object is

Question

An object of mass m moves with constant speed in a circular path of radius R under the action of a force of constant magnitude F. The kinetic energy of object is (A) (1/2) F R (B) FR (C) 2 F R (D) (1/4) F R

Tardigrade Admin · Accepted Answer

KE =(1/2) m v2=(1/2) (F/a) × v2 =(1/2) (F × v2/((v2)R)) =(1/2) F R

Q. An object of mass $m$ moves with constant speed in a circular path of radius $R$ under the action of a force of constant magnitude $F$ . The kinetic energy of object is

$\frac{1}{2} FR$

FR

$2 FR$

$\frac{1}{4} FR$

$K E = \frac{1}{2} m v^{2} = \frac{1}{2} \frac{F}{a} \times v^{2}$
$= \frac{1}{2} \frac{F \times v ^{2}}{( \frac{v ^{2}}{R} )}$
$= \frac{1}{2} FR$

Q. An object of mass m moves with constant speed in a circular path of radius R under the action of a force of constant magnitude F. The kinetic energy of object is

21​FR

FR

2FR

41​FR

KE=21​mv2=21​aF​×v2 =21​(Rv2​)F×v2​ =21​FR

Q. An object of mass $m$ moves with constant speed in a circular path of radius $R$ under the action of a force of constant magnitude $F$ . The kinetic energy of object is

$\frac{1}{2} FR$

$2 FR$

$\frac{1}{4} FR$

$K E = \frac{1}{2} m v^{2} = \frac{1}{2} \frac{F}{a} \times v^{2}$
$= \frac{1}{2} \frac{F \times v ^{2}}{( \frac{v ^{2}}{R} )}$
$= \frac{1}{2} FR$