An object moves at a constant speed along a circular path in a horizontal plane with centre at the origin. When the object is at x=+2 m, its velocity is -4 hat j m / s. The object's velocity (v) and acceleration (a) at x =-2 m will be

Question

An object moves at a constant speed along a circular path in a horizontal plane with centre at the origin. When the object is at x=+2 m, its velocity is -4 hat j m / s. The object's velocity (v) and acceleration (a) at x =-2 m will be (A) v =4 hat i m / s , a =8 hat j m / s 2 (B) v =4 hat j m / s , a =8 hat i m / s 2 (C) v =-4 hat j m / s , a =8 hat i m / s 2 (D) v =-4 hati m / s , a =-8 hat j m / s 2

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<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/c28ca8505d2e555f2f69206e96f80981-.png" /> a c =( V 2/ r )=(42/2)=(16/2)=8 m / s 2 vec V =4 hat j vecac=8 hat i

Q. An object moves at a constant speed along a circular path in a horizontal plane with centre at the origin. When the object is at $x = + 2 m$ , its velocity is $- 4 \hat{j} m / s$ . The object's velocity (v) and acceleration (a) at $x = - 2 m$ will be

$v = 4 \hat{i} m / s, a = 8 \hat{j} m / s^{2}$

$v = 4 \hat{j} m / s, a = 8 \hat{i} m / s^{2}$

$v = - 4 \hat{j} m / s, a = 8 \hat{i} m / s^{2}$

$v = - 4 \hat{i} m / s, a = - 8 \hat{j} m / s^{2}$

$a_{c} = \frac{V ^{2}}{r} = \frac{4 ^{2}}{2} = \frac{16}{2} = 8 m / s^{2}$
$V = 4 \hat{j}$
$a_{c} = 8 \hat{i}$

Q. An object moves at a constant speed along a circular path in a horizontal plane with centre at the origin. When the object is at x=+2m, its velocity is −4j^​m/s. The object's velocity (v) and acceleration (a) at x=−2m will be

v=4i^m/s,a=8j^​m/s2

v=4j^​m/s,a=8i^m/s2

v=−4j^​m/s,a=8i^m/s2

v=−4i^m/s,a=−8j^​m/s2