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Q. An object moves at a constant speed along a circular path in a horizontal plane with centre at the origin. When the object is at $x=+2 m$, its velocity is $-4 \hat{ j } m / s$. The object's velocity (v) and acceleration (a) at $x =-2 m$ will be

JEE MainJEE Main 2023Motion in a Plane

Solution:

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$ a _{ c }=\frac{ V ^2}{ r }=\frac{4^2}{2}=\frac{16}{2}=8\,m / s ^2 $
$\vec{ V }=4 \hat{ j } $
$ \vec{a_c}=8 \hat{ i }$